The new price would be $19.99
29.99 x .6666 = $19.99
(Old price multiplied by discount percentage = new price)
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
I think the closest would be 41.5%
Step-by-step explanation:
If you take the number of passengers left on the plane and divide by the total number of passengers that were on the plane in the beginning, you would get 58.5%. That's the % of how many people are left on the plane. So, you would then do 100%-58.5% to get the answer 41.5%. Hope this helps! :)
The answer is 3
Multiply 6 by 3 to get the total amount of money for the books then minus the answer 18 which you get from 6 x 3 = 18
Then minus 18 from 21 to get $3
21 - 18 = 3
<h2><em>each student requires 9m² of floor </em></h2><h2><em>and given the no. of students is 50
</em></h2><h2><em>So the total area of the room is 9m²X50=450m²
</em></h2><h2><em>Given the length of the room is 25m
</em></h2><h2><em>so the Breadth is =450/25=18m
</em></h2><h2><em>
</em></h2><h2><em>each student requires 108m³ of space </em></h2><h2><em>so total volume of the room is 108X50=5400m³
</em></h2><h2><em>we know that : Volume=Area X h
</em></h2><h2><em> so⇒5400=450Xh
</em></h2><h2><em> ⇒h=5400/450= 12m</em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
