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suter [353]
3 years ago
12

Will mark brainliest help Assume that y varies inversely as x. If, y, is 2.4 when x = 5, which is an equation that relates x and

y?
Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0
Do not click the photo it has a virus
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Can you please help me with question three
horrorfan [7]

Answer:

$34.30

Step-by-step explanation:

He pays 7 percent to health insurance.

7 percent of 490 is 34.30. (490 x 0.07)

ALSO: question 1 answer is actually $298.90

5 0
2 years ago
There were 12 girls on the basketball team. 3 of them scored over 10 points in the game. What fraction represents the number of
Naily [24]

Answer:

1/4

Step-by-step explanation:

3 out of 12 stored over 10:

3 / 12

simplify

1/4

6 0
2 years ago
Given a right triangle, If tan aq=3/4, what is the length of the side adjacent to aq?
olasank [31]
Tan = o/a and = 3/4 so the opposite is 3 and the adjacent is 4
8 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
I NEED IT ASAP HWHAHAHA
vova2212 [387]
Answer: 19/100
explanation: it has a 19% chance so it is 19/100
4 0
3 years ago
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