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Alika [10]
3 years ago
11

Murphy and Naryam do their homework together. When they get to 9 - (-8) they get different answers. Murphy claims that the answe

r is 17 and Naryam claims the answer is -1. Who do you think is correct?
Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:Murphy is right

Step-by-step explanation: When there are two negitives right next to each other the cancel out so it turns into a positive make the question 9+8 making the answer 17.

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What is the square root of -1​
Romashka [77]

Answer:

i

Step-by-step explanation:

Now, before you think I'm just stealing points, let me explain. The square root of a number is the number that, if you multiply it by itself, it equals that number. The square root of 4 is 2, because 2 * 2 = 4.

Also, a negative number times another negative number, is a positive number. -2 * -2 = 4

With both of those true, then what number could be multiplied by itself to equal a negative number? i.

i is a weird number that I don't really know how to explain all that well. I am sorry, but that is all that I can give you. i is very complex and has various different equivalents, and different meanings, but i is equal to \sqrt{-1}.

Hope that this helps!

3 0
3 years ago
An equation of a hyperbola is given.
siniylev [52]

Answer:

a)

The vertices are \left(3,\:0\right),\:\left(-3,\:0\right).

The foci are \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right).

The asymptotes are y=2x,\:y=-2x.

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1 is the standard equation for a right-left facing hyperbola with center \left(h,\:k\right).

a)

The vertices\:\left(h+a,\:k\right),\:\left(h-a,\:k\right) are the two bending points of the hyperbola with center \:\left(h,\:k\right) and semi-axis a, b.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and vertices \left(3,\:0\right),\:\left(-3,\:0\right).

For a right-left facing hyperbola, the Foci (focus points) are defined as \left(h+c,\:k\right),\:\left(h-c,\:k\right) where c=\sqrt{a^2+b^2} is the distance from the center \left(h,\:k\right) to a focus.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 c=\sqrt{3^2+6^2}= 3\sqrt{5} and foci \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)

The asymptotes are the lines the hyperbola tends to at \pm \infty. For right-left hyperbola the asymptotes are: y=\pm \frac{b}{a}\left(x-h\right)+k

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and asymptotes

y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x

b) The length of the transverse axis is given by 2a. Therefore, the lenght is 6.

c) See below.

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