H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer:
x = 5
Step-by-step explanation:
6/18 = x/(20-x)
1/3 = x/(20-x) Multiply both sides by 20-x
(20-x)/3 = x Multiply both sides by 3
20-x = 3x Add x in both sides
20 = 4x Divide both sides by 4
5 = x
Answer:
a)6x = 16
Step-by-step explanation:
<h2><u>Finding the value</u></h2>
the ratio can be solved by <u>cross multiplication :</u>
6 : 2
8 : x
6*x = 8*2
6x = 16
answer is : <u>a) 6x = 16</u>
Answer:
The numbers below are all grater than one:
#2
#3
#4
Step-by-step explanation:
ʕ•ᴥ•ʔ
4 will multiply inside that brackets so
4(x-4)=4x-4
