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2 years ago

WILL MARK BR HELP ME PLZ FAST AS POSSIBLE

Mathematics

1 answer:

posledela2 years ago

8 0

<h2>Answer:</h2>

<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

cos 36= x/8√5+1/4 = x/8

4.7 is the approximate answer

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A total of $12,000 is invested in two corporate bonds that pay 7.5% and 9% simple interest. The invest wants an annual interest

nlexa [21]

Answer:

$13,200

Step-by-step explanation:

You need to use the simple interest formula

I = P * r * t

I = Interest accrued

P = Principal amount invested

r = Interest rate you need to divide by 100 to get it in decimal form

t = time, in years if you are given a partial year, divide the months by 12

P = $12,000

r = 7.5% = .075

t = 1

But, because we want I to equal $990 then I is

I = $990

So we ignore our P and instead solve for the P that will give us the desired result.

I = P * r * t

$990 = P * .075 * 1

$990 = P.075 Divide each side by .075

$990/.075 = P.075/.075

$990/.075 = P

$13,200 = P

So, to earn an annual interest income of $990, $13,200 will have to be invested in the 7.5% bond.

6 0

3 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is $14.28days^{-1}$

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

7 0

3 years ago

Help plsss, i need it asap!!!!! thankss

Elis [28]

With what ??? I don’t see nothing

5 0

3 years ago

Answer 11-12 it’s ok if your don’t no one of them. Please do at least one. Thanks.

Naddika [18.5K]

[11]

Equation: 180° - 75°

Measure: 105°

A straight line has an angle measurement of 180°. Since we have GFB, 75°, we can find EFB this way.

[12]

Equation: 90° - 40°

Measure: 50°

The little box in the angle shows that it is equal to 90°. Since they give us HGB, 40°, we can solve for EFB using this information.

3 0

2 years ago

A garden is 15-feet long by 5-feet wide . The length and width of the garden will each be increased by the same number of feet .

Fittoniya [83]

Answer:

40 + 4x

Step-by-step explanation:

formula for perimeter:

( length * 2 )+(width * 2)

you know that the length and width will be increased by the same number so you can call that X.

((length + x)*2) + ((width + x) * 2)

then substitute length and width

((15+x)*2) + ((5+x)*2))

you can simplify this a bit more

30 + 2x + 10 + 2x

40 +4x

Goodluck with your schoolwork/homework!

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Sorry for any wrong answers or bad explanations.

3 0

3 years ago

Read 2 more answers