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3 years ago

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This isn't a math question. Hellooo!!! Can someone pls help me??? how does racial discrimination relate to economic statificatio

n? :))) If you don't want to.... I mean..... It's okay..... :)))

1 answer:

borishaifa [10]3 years ago

6 0

Im confused on what are you asking

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If u = <2, -5>, v = <3, -2>, and w = <5, -3>, which operation is represented by this graph?

riadik2000 [5.3K]

The answer is B

Because of the equation

I did

7 0

3 years ago

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Geometry One side of a rectangle is 5 inches long. Another side of the rectangle is 7 inches long. What are the lengths of the o

hoa [83]

5 and 7 since rectangles must have a pair of each sides

4 0

3 years ago

Figure 6 shows a semicircle PTS with center O and radius 8cm. QST is a sector of a circle with center S and R is the midpoint of

sveticcg [70]

(a) <TOR=pi/3 radians

To determine <TOR we use the fact that in the right-angled triangle ORT we know two sides:

|OT|=radius=8cm and |OR|=radius/2=4cm

and can use the sine:

$\sin \angle OTR=\frac{r/2}{r}=\frac{1}{2}\implies \angle OTR =\frac{\pi}{6}$

and since <TRO=pi/2, it must be that

$\angle TOR =\pi-\frac{\pi}{2}-\frac{\pi}{6}=\frac{\pi}{3}$

(b) The arc length is approximately 7.255 cm

In order to calculate the arc length QT, we need to first determine the length |ST| and the angle <OST.

Towards determining angle <OST:

$\angle SOT = \pi - \angle TOR = \pi - \frac{\pi}{3} = \frac{2}{3}\pi$

Next, draw a line connecting P and T. Realize that triangle PTS is right-angled with <PTS=pi/2. This follows from the Thales theorem. Since R is a midpoint between P and O, it follows that the triangles ORT and PRT are congruent. So the angles <PTR and <OTR are congruent. Knowing <PTS we can determine angle <OTS:

$\angle OTR \cong \angle PTR=\frac{\pi}{6}\implies\angle OTS=\angle PTS -\angle PTR -\angle OTR\\\angle OTS = \frac{\pi}{2}-\frac{\pi}{6}-\frac{\pi}{6}=\frac{\pi}{6}$

and so the angle <OST is

$\angle OST = \pi - \angle TOS - \angle OTS = \pi -\frac{2}{3}\pi - \frac{1}{6}\pi=\frac{\pi}{6}$

Towards determining |TS|:

Use cosine:

$\cos \angle OST =\frac{|RS|}{|ST|}\implies |ST|=\frac{\frac{3}{2}r}{\cos \frac{\pi}{6}}=\frac{12\cdot 2}{\sqrt{3}}=8\sqrt{3}cm$

Finally, we can determine the arc length QT:

$QT = {\angle OST}\cdot |ST|=\frac{\pi}{6}\cdot 8 \sqrt{3}=\frac{4\pi}{\sqrt{3}}\approx 7.255cm$

3 0

3 years ago

Find the exact value of cos2theta if sin2theta=3/4 and theta is between 0 and 90 degree

sammy [17]

<h2> <u>Answer</u> :</h2>

$\boxed{ \boxed{ \cos {}^{2} ( \theta) = \dfrac{1}{4} }}$

<h2><u>Solution</u> :</h2>

According to a Trigonometric Identity :

$\hookrightarrow \mathrm{\sin {}^{2} ( \theta) + \cos {}^{2} ( \theta) = 1}$

Now, let's solve for $\cos²(\theta)$

$\longrightarrow \dfrac{3}{4} + \cos {}^{2} ( \theta) = 1$

$\longrightarrow \cos{}^{2}( \theta) = 1 - \dfrac{3}{4}$

$\longrightarrow \cos {}^{2} ( \theta) = \dfrac{4 - 3}{4}$

$\longrightarrow \cos {}^{2} ( \theta) = \dfrac{1}{4}$

$\large\mathfrak{{\pmb{\underline{\orange{hope \: \: it \: \: helps \: \: you.....}}{\orange{}}}}}$

4 0

3 years ago

1)Choose one of the factors of 24x6 - 1029y3 (24x to the sixth power minus 1029y to the third power) A)3 B)2x2 - 7y C)4x4 + 14x2

grigory [225]

24x⁶ - 1029y³ =
3(8x⁶ - 343y³) =
3((2x²)³ - (7y)³) =
3(2x²-7y)(4x⁴ + 14x²y + 49y²)

Answer is <span>D) All of the above.</span>

5 0

3 years ago

Read 2 more answers