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astra-53 [7]
3 years ago
15

My father is 47 years old. I am x years old.

Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

your father 47+y You x+y

Step-by-step explanation:

Your father is 47 + y years old after y years

You will be x + y years old after y years.

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Which image would provide a good counterexample to the statement below?
wariber [46]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Ramos went to a pizza shop and spent half of his money on lunch. If Ramos had $4.50 left after lunch, how much money did he have
blondinia [14]

The Answer is $9.00 because if you just add 4.50 to 4.50 it is $9:00.

7 0
3 years ago
What is the shortest Hamilton path for the vertex-edge graph?
marin [14]

Answer:

The first one is the answer

3 0
3 years ago
10. Explain why log328 is between 3 and 4.
maw [93]

Answer:

See explanation.

(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)

Step-by-step explanation:

I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.

3^0=1

3^1=3

3^2=9

3^3=27

3^4=81

3^5=243

......

I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.

log_3(28) means the value x such that 3^x=28.

Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.

8 0
3 years ago
Carlos has at most $40 to spend on food for a barbeque. He wants to buy hot dogs and hamburgers and then
poizon [28]

Answer:

$8.50

Step-by-step explanation:

I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:

($31.50) + r \leq $40

This says the sum of what Carlos has already spent (hot dogs and hamburgers) plus the amount he spends on Alls (rolls?), r,  must be equal to or less than the $40 he has allowed himself to spend.

($31.50) + r \leq $40

r  \leq $40 - $31.50

r \leq $8.50

3 0
2 years ago
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