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2 years ago

What are the common factors of 16 and 24?

Mathematics

1 answer:

scZoUnD [109]2 years ago

7 0

Answer:

1 , 2 , 4 , 8

Step-by-step explanation:

Factors of 16:

1, 2, 4, 8, 16

Factors of 24:

1, 2, 3, 4, 8, 6, 12, 24

Common factors are factors that are shared by both numbers, in this case, it i: 1 , 2 , 4, 8

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Solve each compound inequality. Graph your solutions.<br> 5 + m > 4 or 7m< -35

Yuliya22 [10]

Answer:

Solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality $5 + m > 4\: or\: 7m< -35$

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

$5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m$

So, solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

5 0

2 years ago

Converting ounces to pounds

Bond [772]

There are 16 ounces in 1 pound.

8 0

3 years ago

Why can you NOT combine 3x and 5x^2 ?

diamong [38]

Although they are the same variable, you cannot add two variables raised to different powers. 3x^1 + 5x^2 cannot work, but 3x^2 + 5x^2 can. Also, if you are multiplying them, they would combine to be 15x^3, as 3 and 5 (The coefficients) multiply together and x^2 times x^1 = x^3.

I hope that helps.

7 0

3 years ago

Corey went shopping and bought a pair of shoes for $65.99 and two caps for $15.99 each. If he was charged a sales tax of 8%, the

RUDIKE [14]

Answer:

It’s 105

Step-by-step explanation:

6 0

2 years ago

Find the tenth term of the geometric sequence, given the first term and common ratio.

Natalija [7]

Answer:

$a_{10}=\dfrac{1}{128}$

Step-by-step explanation:

In the geometric series:

$a_1=4\\ \\r=\dfrac{1}{2}$

The nth term of the geometric sequence can be calculated using formula

$a_n=a_1\cdot r^{n-1}$

In your case, n = 10, then

$a_{10}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^{10-1}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^9\\ \\=2^2\cdot \dfrac{1}{2^9}\\ \\=\dfrac{1}{2^{9-2}}\\ \\=\dfrac{1}{2^7}\\ \\=\dfrac{1}{128}$

8 0

2 years ago