the perimeter of a triangle is 34 units. its width is 6.5 units. write an equation to determine the length (l) of the rectangle

1 answer:

3 0

Perimeter = length of the 3 sides of the triangle ie 34units

Since width we are given 6.5 units

We have to find the remaining 2 sides:

Formula of Triangle for Perimeter

P = a + b + c (sum of sides)

simplify: P= a + 2b (its an isosceles)

34 = 6.5 + 2b

34 - 6.5 = 2b

27.5 = 2b

Só b = 13.75 units each length of triangle

Relationship between triangle and rectangle

= rectangle has four right angles, so a triangle has an angle of half since it bisects the edges (ie 45*)

Use Trig Ratios to find L

SOHCAHTOA

we want adjacent ( L)

13.75 sin 45

L = 9.72

Thus your equation is

Equation used to find Triangle × Trig ratios

P = a + 2b
sin 45

Where L is length of rectangle
a is width of triangle

L =(P - a +2b)× sin 45

You might be interested in

<br> PLS help me with this. And I am so sorry if im troubling you

dedylja [7]

Answer:

a=70 vertically opp angles

b=80 linear pair

c=100 corresponding angles

d= 80 linear pair with c

e= 180 -a-d

=180-70-80

=30

8 0

2 years ago

One way of solving systems of linear equations is by adding a multiple of one equation to the other. the multiplier for one equa

elena-s [515]

We want to use elimination to solve
y = 0 (1)
x + y = 40 (2)

Multiply (1) by -1 to eliminate y.
-y = 0 (3)

Add (2) and (3).
x + y + (-y) = 40 + 0
x = 40

Answer: Multiply by -1.

3 0

3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got: