the perimeter of a triangle is 34 units. its width is 6.5 units. write an equation to determine the length (l) of the rectangle

1 answer:

3 0

Perimeter = length of the 3 sides of the triangle ie 34units

Since width we are given 6.5 units

We have to find the remaining 2 sides:

Formula of Triangle for Perimeter

P = a + b + c (sum of sides)

simplify: P= a + 2b (its an isosceles)

34 = 6.5 + 2b

34 - 6.5 = 2b

27.5 = 2b

Só b = 13.75 units each length of triangle

Relationship between triangle and rectangle

= rectangle has four right angles, so a triangle has an angle of half since it bisects the edges (ie 45*)

Use Trig Ratios to find L

SOHCAHTOA

we want adjacent ( L)

13.75 sin 45

L = 9.72

Thus your equation is

Equation used to find Triangle × Trig ratios

P = a + 2b
sin 45

Where L is length of rectangle
a is width of triangle

L =(P - a +2b)× sin 45

You might be interested in

What two numbers multiply to -126 and add up to -65

Airida [17]

Xy = -126
x + y = -65

$xy = -126$
$\frac{xy}{x} = \frac{-126}{x}$
$y = \frac{-126}{x}$

$x + y = -65$
$x + \frac{-126}{x} = -65$
$\frac{x^{2}}{x} + \frac{-126}{x} = -65$
$\frac{x^{2} - 126}{x} = -65$
$-65x = x^{2} - 126$
$0 = x^{2} + 65x - 126$
$x = \frac{-(65) \+ \sqrt{(65)^{2} - 4(1)(-126)}}{2(1)}$
$x = \frac{-65 \± \sqrt{4225 + 504}}{2}$
$x = \frac{-65 \± \sqrt{4729}}{2}$
$x = \frac{-65 \± 68.8}{2}$
$x = \frac{-65 + 68.8}{2}$ $or$ $x = \frac{-65 - 68.8}{2}$
$x = \frac{3.8}{2}$ $or$ $x = \frac{-133.8}{2}$
$x = 1.9$ $or$ $x = -66.9$

x + y = -65
  1.9 + y = -65
- 1.9   - 1.9
y = -66.9
  (x, y) = (1.9, -66.9)

or

  x + y = -65
  -66.9 + y = -65
+ 66.9 + 66.9
y = 1.9
  (x, y) = (-66.9, 1.9)

The two numbers that add up to -65 and can multiply to -126 are the numbers -66.9 and 1.9.

3 0

3 years ago

Find the exponential equation for the given information. Pls help

nikitadnepr [17]

Answer:

y = 12 $(2.9)^{x}$