If the third term of the aritmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Given the third term of the aritmetic sequence is 126 and sixty fourth term is 3725.
We are required to find the first term of the arithmetic sequence.
Arithmetic sequence is a series in which all the terms have equal difference.
Nth term of an AP=a+(n-1)d
=a+(3-1)d
126=a+2d--------1
=a+(64-1)d
3725=a+63d------2
Subtract second equation from first equation.
a+2d-a-63d=126-3725
-61d=-3599
d=59
Put the value of d in 1 to get the value of a.
a+2d=126
a+2*59=126
a+118=126
a=126-118
a=8
=a+(1-1)d
=8+0*59
=8
Hence if the third term of the arithmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Learn more about arithmetic progression at brainly.com/question/6561461
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Answer:
0.025 Kg/ cm²
Step-by-step explanation:
if two variables vary inversely, there is a negative relationship between both variables. the increase in one variable leads to a decrease in the other variable
the equation that represents inverse proportion :
where b = constant of proportionality
to determine the answer in this question :
1. determine constant of proportionality
200 = k / 32
k = 6400
2. Determine the amount of pressure using the constant of proportionality
256, 000 = 6400 / pressure
pressure = 6400 / 256, 000 = 0.025
Answer: $17.94
Step-by-step explanation:
The answer to thus problem is 269. 7
The answer is 13
Euler's formula:
F + V - E = 2
F - number of faces
V - number of vertices
E - number of edges
We have:
F = 7
V = ?
E = 18
7 + V - 18 = 2
7 + V = 2 + 18
7 + V = 20
V = 20 - 7
V = 13
