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Kipish [7]
3 years ago
5

Can some one help me with this ?

Mathematics
1 answer:
irinina [24]3 years ago
4 0

Answer:

x= 91°

Step-by-step explanation:

Sum of all angles in a triangle is 180°

So 180 - 44 - 45 = 91

x = 91

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Can someone help me ill give brainles
avanturin [10]

what do you need help with?

6 0
3 years ago
Solve each system using elimination. 3x+3y=27 x-3y=-11
Natalija [7]

Answer:

x=4

y=10

Step-by-step explanation:

3x +3y = 27

x - 3y = -11 (add these up so 3y will be eliminated and you'll have x only)

4x = 16

now let's eliminate x (you can put 4 instead of x though)

3x + 3y = 27

-3/ x -3y= -11 (multiple the the 2nd equation with -3 to eliminate x )

3x + 3y =27

-3x + 3y =33

6y = 60

8 0
4 years ago
List the following in order from least to greatest<br><br> -3/5, -0.4, -1, -0.5
nikklg [1K]

-1

- 3/5

- 0.5

-0.4

The least is always the one furthest away from 0

5 0
4 years ago
What is 244 divided by 60 with remainders
Troyanec [42]
244 divided by 60 = 4.0666
3 0
3 years ago
Read 2 more answers
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
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