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ASHA 777 [7]
3 years ago
13

HELP 4 - x = 3x - 8 + 2x

Mathematics
1 answer:
USPshnik [31]3 years ago
6 0

The answer is x=2 :) ✨

Hope it helps

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Car leases generally allow only a certain number of miles to be driven. Myung’s lease included a charge of 25 cents per mile for
faust18 [17]

Answer:

36,000

Step-by-step explanation:

if you multiply 12,000 and 3 you get 36,000.

4 0
3 years ago
-6(a + 8)<br> I need help!
Yuliya22 [10]

Answer: I got -6a + 48

Step-by-step explanation:I distributed and I got negative 6a because when you distributed the variable goes with whatever number is before it and I got 48 because -6 multiplied by 8 you get positive 48 because the 8 is bigger then the negative 6 so I don't know if your teacher wants you to solve for the answer but like I said I got -6a + 48

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3 years ago
Solve by using the quadratic formula: Simplify
larisa [96]

Answer:

-6 - square root 31, -6 + square root 31

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2 years ago
Read 2 more answers
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
UJUU J
Stels [109]

Answer:

Plese read the complete procedure below:

Step-by-step explanation:

The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)

a)

1   -6   3   26   -24    |<u>  1     </u>

<u>      1   -5   -2    24</u>

1   -5   -2   24    0

The remainder is zero, then (a-1) is a factor of the polynomial

b)

1   -6   3   26   -24    |<u>  2     </u>

<u>      2  -8   10    72</u>

1   -4   5   36    48

When p(a) is divided by (a-2) the remainder 28/p(a)

1   -6   3   26   -24    |<u> - 4     </u>

<u>    -4  40  172  -792</u>

1   -10  43  198  -816

When p(a) is divided by (a-2) the remainder -816/p(a)

c) I attached an image of the long division below:

3 0
3 years ago
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