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hichkok12 [17]
3 years ago
14

Whats the domain and range of the relation

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

See below in bold.

Step-by-step explanation:

The domain is the list of x values and the range is the list of y values.

Reading from the graph: The domain is {-3.5, -2, 0, 3.5}.

The range is {3, 1.5, -0.5, }.

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Simplify the expression: -1/2 (-5/6 + 1/3)
Kazeer [188]

Answer:

Exact Form:

1/6

Decimal Form:

0.16 (6 repeating)

Step-by-step explanation:

3 0
3 years ago
What is the surface area of the right cylinder below?
IgorLugansk [536]

Answer:

Ok to find the surface area of this cylinder first we need the circumference to find this we do C=πd

C=3.14*18

C=56.52

now we have to multiple this by the height of two

113.04

now we have to find the area of the bottom to do this we do A=πR^2

A=3.14*81

A=254.34

multiple this by two for the two sides we get

508.68

now we add this to 113.04 we get

621.72

since I used 3.14 instead of more digits of pie we can round this up so the answer is C.

Your Welcome

BIFFY OUT!!!

8 0
2 years ago
The formula for the volume of a cylinder is V = pir2h. Solve the formula for the height h.
RideAnS [48]
H=v/(2pir)

You just have to isolate h. To do that you are going to divide both sides by 2pir. 
5 0
2 years ago
Find the exact area of a circle having the given circumference.
blagie [28]

Answer:

<h2>A = 2.25π</h2>

Step-by-step explanation:

The formula of an area of a circle:

A=\pi r^2

r - radius

The formula of a circumference of a circle:

C=2\pi r

We have:

C=3\pi

Substitute:

2\pi r=3\pi            <em>divide both sides by 2π</em>

r=1.5

Substitute:

A=\pi(1.5)^2=2.25\pi

3 0
3 years ago
Decide whether the relation is a function?
Nana76 [90]

Answer:

A property of a function is that it gives one output for an input

if a function gives one output for an input, it is a function and otherwise it is not a function otherwise

here, we can see that we have 2 outputs for the input '6'. therefore, it is NOT a function

3 0
2 years ago
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