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3 years ago

Need the answer ASAP

Mathematics

1 answer:

balu736 [363]3 years ago

4 0

Answer:

(-7, 5)

Step-by-step explanation:

Since both of them are equal to y, you could just set them equal to each other.

5/7x + 4 = -1/7x - 2

6/7x = -6

x = -7

Now just plug x back to one of the equations:

y = -1/7*(-7) - 2 = 7 - 2 = 5

Therefore, the solution to the system is (-7, 5)

You might be interested in

What do outliers, mean, median, mode, and range tell you PLEASE SHOW EXAMPLES!!!!!!

Zanzabum

Hello there!

Outlier is a value in a data set that varies significantly from the rest of the data.

Example: Way too low: 1, 45, 58, 60, 63, 75

Outlier = 1

Way too high: 4, 3, 2, 21, 7

The number should be the order from least to greatest are: 2, 3, 4, 7, 21.

Outlier = 21

It impact the mean and the median in different ways.

Data with no outlier: 4, 5, 7, 11, 12, 15

54÷6=9

Mean = 9

Data with an outlier: 4, 5, 7, 11, 12, 15, 58

112÷7=16

Mean = 16

Median is the middle value in an ordered list of numbers.

Example:

Numbers already in order:

1, 5, 8, 10, 13

Numbers not already in order:

13, 1, 5, 10, 8

1, 5, 8, 10, 13, 15

8+10=18 or 18÷2=9

Median =9

Range is a difference between the maximum (highest) and minimum (lowest) values. It has one type of measure of spread.

Example:

Data in order: 23, 27, 39, 53, 62, 84

84-23=61

Data not in order: 272, 52, 67, 201, 43, 256

272-43=229

Hope this helps! Thank you for posting your question at here on Brainly.

-Charlie

3 0

3 years ago

There is a ratio of 5girls to 3boys there are 24 boys how many girl

MissTica

40 just multiply by 8

5 0

3 years ago

The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of

Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is, $\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4$

The standard deviation of this sample is 2. That is, $s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2$ .

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

$\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5$

The new mean is 5.

Compute the standard deviation of this sample as follows:

$s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s$

The new standard deviation is also 2.

5 0

3 years ago

boyakko [2]

The missing part in the question;

and the payoff is $2.20 won for every dollar bet. (As the player’s probability of winning in this case is $\dfrac{1}{4}$ ........

Also:

For such a bet, the casino pays off as shown in the following table.

The table can be shown as:

Keno Payoffs in 10 Number bets

Number of matches Dollars won for each $1 bet

0 - 4 -1

5 1

6 17

7 179

8 1299

9 2599

10 24999

Answer:

Step-by-step explanation:

Given that:

Twenty numbers are selected at random by the casino from the set of numbers 1 through 80

A player can select from 1 to 15 numbers; a win occurs if some fraction of the player’s chosen subset matches any of the 20 numbers drawn by the house

Let assume X to represent the numbers of player chooses which are in the Casino-selected-set of 20.

Let assume the random variable X has a hypergeometric distribution with parameters N= 80 and m =20.

Then, the probability mass function of a hypergeometric distribution can be defined as:

$P(X=k)=\dfrac{(^m_k)(^{N-m}_{n-k})}{(^N_n)}, k =1,2,3 ... n$

Now; the probability that i out of n numbers chosen by the player among 20 can be expressed as:

$P(X=k)=\dfrac{(^{20}_k)(^{60}_{n-k})}{(^{80}_n)}, k =1,2,3 ... n$

Also; given that ; When the player selects 2 numbers, a payoff (of odds) of $12 won for every $1 bet is made when both numbers are among the 20

So; n= 2; k= 2

Then :

Probability P ( Both number in the set 20) $=\dfrac{(^{20}_2)(^{60}_{2-2})}{(^{80}_2)}$

Probability P ( Both number in the set 20) $= \dfrac{20*19}{80*79}$

Probability P ( Both number in the set 20) $=\dfrac{19}{316}$

Probability P ( Both number in the set 20) $=\dfrac{1}{16.63}$

Thus; the payoff odd for $=\dfrac{1}{16.63}$ is 16.63:1 ,as such fair payoff in this case is $16.63

Again;

Let assume X to represent the numbers of player chooses which are in the Casino-selected-set of 20.

Let assume the random variable X has a hypergeometric distribution with parameters N= 80 and m =20.

The probability mass function of the hypergeometric distribution can be defined as :

$P(X=k)=\dfrac{(^m_k)(^{N-m}_{n-k})}{(^N_n)}, k =1,2,3 ... n$

Now; the probability that i out of n numbers chosen by the player among 20 can be expressed as:

$P(n,k)=\dfrac{(^{20}_k)(^{60}_{n-k})}{(^{80}_n)}, k =1,2,3 ... n$

From the table able ; the expected payoff can be computed as shown in the attached diagram below. Thanks.

8 0

3 years ago

Write an equation of the line pictured in the graph

8090 [49]

Y=1/2x+2 s the answer

3 0

3 years ago