All categories

2 years ago

10. Find the outlier of the set of data: 30, 54, 47, 45, 42, 50, 54, 49 (1 point)

Mathematics

1 answer:

Likurg_2 [28]2 years ago

5 0

Answer:It would be 30!

Step-by-step explanation:

You need to line them all up in order and then see the one that sticks out from all of the others. All the other numbers are in the 40s and 50s and this one is 30.

You might be interested in

A piece of electronic equipment is built with 3 cooling fans. The equipment will function only if at least 2 of the 3 fans are w

PolarNik [594]

Answer:

0.66608

Step-by-step explanation:

Equipment = 3 fans

Mortality = 0.098

We are required to find probability that equipment gets to work for 5years

The question says forces of mortality is constant and also equal to 0.098

To calculate p(x>5)

We will do this by calculating exponentially

e^-0.098x5

= 0.612626394

Probability that at least 2 fans out of 3 are working

3(0.612626394)²+(1-0.612626394)+(0.612626394)³

= 1.1259333x0.3873736+0.2299255

= 0.6660823470

This is approximately

<u>0.6608</u>

this is the probability that the equipment will work for at least 5years

8 0

2 years ago

can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as

tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: $a*r^{n-1}$ . The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = $a*r^{n-1}$ , we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: $k * 0.75^{n-1}$ . This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. $n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft$

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is $\frac{a(1 - r^{n})}{1-r}$ , provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

$\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft$

6 0

2 years ago

Can someone help me? Files attached! <br> What answer choices go to what figure? :D

den301095 [7]

Since the center is considered the corner that they both share, here are the answers figure a goes with the first, figure b goes with the last, figure c goes with the second, and figure d goes with the third. Hope this helps.

3 0

3 years ago

Please help I'll give brainiest

Komok [63]

For the first is 3864
The second is 1320
A=3.14(which is pie) x 20.5^2
A=420x pie
A=1320
For the third is 2544
3864-1320=2544
Sorry if this is wrong too.

8 0

2 years ago

Read 2 more answers

The disk enclosed by the circle x+y = 4 is revoived about the y-axis to generate solid sphere. A hele of diameter 2 units is the

Vesnalui [34]

Step-by-step explanation:

Suppose we have a curve, y = f(x).

y = f(x)

x = a x = b

Imagine that the part of the curve between the ordinates x = a and x = b is rotated about the

x-axis through 360◦

. The curve would then map out the surface of a solid as it rotated. Such

solids are called solids of revolution. Thus if the curve was a circle, we would obtain the surface

of a sphere. If the curve was a straight line through the origin, we would obtain the surface of

a cone. Now we already know what the formulae for the volumes of a sphere and a cone are,

but where did they come from? How can they calculated? If we could find a general method

for calculating the volumes of the solids of revolution then we would be able to calculate, for

example, the volume of a sphere and the volume of a cone, as well as the volumes of more

complex solids.

To see how to carry out these calculations we look first at the curve, together with the solid it

maps out when rotated through 360◦

y = f(x)

Now if we take a cross-section of the solid, parallel to the y-axis, this cross-section will be a

circle. But rather than take a cross-section, let us take a thin disc of thickness δx, with the face

of the disc nearest the y-axis at a distance x from the origin.

www.mathcentre.ac.uk 2

6 0

3 years ago