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2 years ago

2 3/4+1 1/5 i need this for math, im kinda stupid, please dont anwser if you dont know its for a test XD

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

5 0

Answer:

3 19/20

Step-by-step explanation:

So...

The first step is to find a common denominator between the 2. The smallest common denominator is 20. So you would do 3/4 times 5/5 which is 15/20. (2 15/20)

1/5 times 4/4 = 4/20(1 4/20)

So the final step is to add them together

2 15/20 + 1 4/20= 3 19/20.

This is the most simplified answer you can get.

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3 years ago

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3 years ago

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The perimeter of a rectangle room is 250 feet the length is 35 feet less than three times the width what is the length of the ro

raketka [301]

Perimeter of rectangle:
P = 2(L + W)
P = 250 (given)
L = 3W - 35 (given)

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6 0

3 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

2 years ago

F (n) = 65 - 100n<br> f (39) =

yan [13]

f(39)=65-100(39)

65-3900

= -3835

6 0

2 years ago