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3 years ago

Pls help it is due today

Mathematics

2 answers:

Eddi Din [679]3 years ago

7 0

Answer:

choice 1) 4 : 2

Step-by-step explanation:

ivann1987 [24]3 years ago

6 0

Answer:

4:2

Step-by-step explanation:

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1.Find by factors the square root of 3600 2. Find by factors the cube root of 343

Contact [7]

Answer:

1)60

2)7

Step-by-step explanation:

1)The square root of 3600 is 60. It is the positive solution of the equation x2 = 3600. The number 3600 is a perfect square.

2)The cube root of 343 is the number which when multiplied by itself three times gives the product as 343. Since 343 can be expressed as 7 × 7 × 7. Therefore, the cube root of 343 = ∛(7 × 7 × 7) = 7.

4 0

3 years ago

Read 2 more answers

Solve 8x + c = kfor x. A. X = 8(k+c) B. x = k-c/8 C. x = k+c/8 D. X = 8(k- c).

Andru [333]

Answer:
Option B

Explanation:
Check out my work I attached

Hope it helps, Let me know if you have any other questions !
Have a nice rest of your day :)

5 0

2 years ago

The rod is made of A-36 steel and has a diameter of 0.22 in . If the rod is 4 ft long when the springs are compressed 0.7 in . a

ziro4ka [17]

The force in the rod when the temperature is 150 °F is 718.72 pounds-force.

<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>

Let suppose that rod experiments a quasi-static deformation and that both springs have a linear behavior, that is, force ( $F$ ), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to temperature increase creates a spring deformation additional to that associated with mechanical contact.

Given simmetry considerations, we derive an expression for the spring force ( $F$ ), in pounds-force, as a sum of mechanical and thermal effects by principle of superposition:

$F = k\cdot (\Delta x + 0.5\cdot \Delta l)$ (1)

Where:

$k$ - Spring constant, in pounds-force per inch.
$\Delta x$ - Spring deformation, in inches.
$\Delta l$ - Rod elongation, in inches.

The rod elongation is described by the following thermal dilatation formula:

$\Delta l = \alpha \cdot L_{o}\cdot (T_{f}-T_{o})$ (2)

Where:

$\alpha$ - Coefficient of linear expansion, in $\frac{1}{^{\circ}F}$ .
$L_{o}$ - Initial length of the rod, in inches.
$T_{o}$ - Initial temperature, in degrees Fahrenheit.
$T_{f}$ - Final temperature, in degrees Fahrenheit.

If we know $k = 1000\,\frac{lb}{in}$ , $\Delta x = 0.7\,in$ , $\alpha = 6.5\times 10^{-6}\,\frac{1}{^{\circ}F}$ , $L_{o} = 48\,in$ , $T_{o} = 30\,^{\circ}F$ and $T_{f} = 150\,^{\circ}F$ , then the force in the rod at final temperature is:

$F = \left(1000\,\frac{lb}{in} \right)\cdot \left[0.7\,in + 0.5\cdot\left(6.5\times 10^{-6}\,\frac{1}{^{\circ}F} \right)\cdot (48\,in)\cdot (150\,^{\circ}F-30\,^{\circ}F)\right]$

$F = 718.72\,lbf$

The force in the rod when the temperature is 150 °F is 718.72 pounds-force. $\blacksquare$

To learn more on deformations, we kindly invite to check this verified question: brainly.com/question/13774755

3 0

3 years ago

Solve log2(6-2x)-log2x=3

Elenna [48]

Assuming you have log in base 2.

Join logarithms (always):

log2(6-2x)-log2(x) = log2( (6-2x/x) )

Then get rid of it! :)

(6-2x)/x = 2^3=8,

Solve the equation:

6-2x=8x ---> 10x=6 ---> x = 3/5.

6 0

3 years ago

What is 10,000, 000,000,000,000,000 x 38=?

Natalka [10]

Answer:

380000000000000000000

Step-by-step explanation:

8 0

3 years ago