1.) Let their speed be x, then distance travelled = speed x time
1.5x + 2.5x = 240
4x = 240
x = 240/4 = 60
Their speed is 60 miles per hour.
2.) Let catie's brother's age be x, then catie's age is 3 + x
x + 3 + x ≤ 31
Required inequality is 2x + 3 ≤ 31
2x ≤ 31 - 3
2x ≤ 28
x ≤ 28/2
x ≤ 14
Therefore, the oldest age Catie's brother can be is 14 years old.
3.) Let June's age be x, then her father's age is 6x
6x + x ≥ 77
7x ≥ 77
x ≥ 77/7
x ≥ 11
The youngest age Julio can be is 11 years old.
Answer:
<u> Consecutive Interior Angles </u>
Consecutive interior angles equal 180 degrees and they are the ones in between(inside) the parallel lines, so that means that these angles..
∠2+∠9= 180
∠4+∠11= 180
∠6+∠13= 180
∠8+∠15= 180
<u> Consecutive Exterior Angles </u>
Consecutive exterior angles also equal 180 degrees, but they are on the outside of the parallel lines. They are...
∠1+∠10= 180
∠3+∠12= 180
∠5+∠14= 180
∠7+∠16= 180
Hello,
I note (a,b,c) the result of a quarters, b dimes and c pennies:
2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)
106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0