Answer:
The simplyfied version would be 19/4
Show of work:
(1/4)^-2 = 4^2
3 × 8^2/3 × 1 = 12
(9/16)^1/2 = 3/4
4^2 - 12 + 3/4
Convert elements to fractions:
-12 × 4 + 3
---------- ----
4 4
Since the denominators are equal combine the fractions:
-12 × 4 + 3
---------------
4
-12 × 4 + 3 = -45
= -45/4
=4^2 - 45/4
4^2 = 16
16 - 45/4
16 × 4 - 45. 16 × 4 - 45
--------- ----- ----------------
4 4. 4
-> 16 × 4 - 45 = 19
= 19/4
The LCD of 3 and 4 is 12. To make 4 into 12, we multiply it by three, so 3 would also have to be multiply by 3, turning 3/4 into 9/12.
The same thing applies to 1/3, only it needs to be multiplied by 4. So it would become 4/12
9/12 - 4/12 = 5/12
<span>first, we are going to define variables as the following:
a = 0
a = π/2
n = 4 rectangles
Δx = [ b - a ] / n ------>Δx = [ π/2 - 0 ] / 4 = π/8
right endpoints :
sum( seq( 4 cos(x) * π/8 , x , 0+π/8 , π/2 , π/8 ) ) = 3.163065 underestimate
left endpoints:
sum( seq( 4 cos(x) * π/8 , x , 0 , π/2-(π/8) , π/8 ) ) = 4.733861 overestimate
the reason because the actual estimate by integral as the following:
π/2
∫ 4cos(x) dx = 4
0</span>
Answer:
B he used the incorrect formula for the volume of the prism
Answer:
Both child tickets and senior tickets cost $14.
Step-by-step explanation:
Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:
10 senior tickets + 8 child tickets = 252
10 senior tickets + 10 child tickets = 280
280 - 252 = 2 child tickets
28 = 2 child tickets
28/2 = 1 child ticket
14 = 1 child ticket
14 x 10 = 140
(280 - 140) / 10 = senior tickets
140/10 = 14 = senior tickets
Therefore, both child tickets and senior tickets cost $14.
