We have that the fourth term of an arithmetic sequence is
a_4=14
Option C
From the question we are told
What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
A) 78
B) 32
C) 14
(Explain your work)
Generally the equation for the arithmetic sequence is mathematically given as
Therefore
For seventh term
Therefore
For Fourth term
a_4=14
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Answer:
the perimeter is 36
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
<u>Equation A</u>
16x - 7 = 11x - 32
(16x - 7) - 11x = (11x - 32) -11x
5x - 7 = -32
(5x - 7) + 7 = (-32) + 7
5x = -25
(5x)/5 = (-25)/5
x = -5
<u>Equation B</u>
-4x - 10 = 2x + 20
(-4x - 10) - 2x = (2x + 20) - 2x
-6x - 10 = 20
(-6x - 10) + 10 = (20) + 10
-6x = 30
(-6x)/-6 = (30)/-6
x = -5
Both Equation A and Equation B have a solution of -5.
f(x) = -4x + 1
g(x) = 2x - 3
Set each other equal and solve for x.
-4x + 1 = 2x - 3
-6x = -4
x = 2/3
substitute x into either f or g and solve for y
-4(2/3) + 1
y = -1.667...
Intersect at
(.667,-1.667)
Divide 42 by 2 and get 21.
