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Mashutka [201]
3 years ago
5

What are the seven steps needed to reconcile a bank statement?

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

1. Add Deposits

2. Bank Errors

3. Outstanding Checks

4. Check Register Reconciliation

5. Interest Earned

6. Check Register Errors

7. Compare Both Statements

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X - 15 = -20 please show work
Natasha2012 [34]

Answer:

x = -5

Step-by-step explanation:

x - 15 = -20

  + 15  + 15

x = -5

5 0
4 years ago
Read 2 more answers
Pls help me with this problem!!!!
kolbaska11 [484]

Answer: 55°

Step-by-step explanation:

∠YAZ + ∠YAX = 180° because they are linear pairs

∠YAZ + ∠YAX = 180°

∠YAZ + 125 = 180

Subtract both sides by 125

∠YAZ = 55°

Hope that helped!

8 0
3 years ago
To qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 an
kolbaska11 [484]

Answer:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

Step-by-step explanation:

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X ~ N (200,20)

For u = 200 and o = 20

For this case we can use the z score in order to solve this problem, given by this formula:

Z = x-u/o

For this part we want to find a value a, such that we satisfy this condition:

P (X > a) = 0.1 (a)

P (X < a) = 0.9 (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P ( X < a) = P (X-u/o < a - u/o) = 0.9

P (z < a-u/o) = 0.9

But we know which value of z satisfy the previous equation so then we can do this:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

3 0
3 years ago
We saw two distributions for triathlon times: N(µ = 4313, Ï = 583) for Men, Aged 30 - 34 and N(µ = 5261, Ï = 807) for the Wome
zzz [600]

Answer:

a) 3354 seconds

b) 6294 seconds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) The cutoff time for the fastest 5% of athletes in the men's group, i.e. those who took the shortest 5% of time to finish.

\mu = 4313, \sigma = 583

The cutoff for the shortest 5% is the 5th percentile, which is X when Z has a pvalue of 0.05. So X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 4313}{583}

X - 4313 = -1.645*583

X = 3354

Cutoff of 3354 seconds.

(b) The cutoff time for the slowest 10% of athletes in the women's group.

\mu = 5261, \sigma = 807

The slowest 10% is the 10% that takes more time, so the cutoff is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 5261}{807}

X - 5261 = 1.28*807

X = 6294

Cutoff time of 6294 seconds

5 0
4 years ago
System of equations <br> 3x-2y=8<br> -2x+5y=-9<br> x=<br> y=
natka813 [3]

Answer:

2y = 3x - 8

y = 3/2x - 4

Work

-2x + 5(3/2x - 4) = -9

-2x + 15/2x - 20 (+20) = -9 (+20)

-4/2x + 15/2x = 11

11/2x * (2/11) = 11 (2/11)

x = 2

3(2) - 2y = 8

6 (-6) - 2y = 8 (-6)

-2y = 2

y = - 1

final answer:

x = 2

y = -1

7 0
4 years ago
Read 2 more answers
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