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jeyben [28]
2 years ago
8

I need help with this problem!

Mathematics
1 answer:
lana [24]2 years ago
3 0

Answer:

IH

Hope this helps!

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What is the average rate of change for 5/6 and 15/14
andreev551 [17]

Answer:

Average rate of change is <u>0.80.</u>

Step-by-step explanation:

Given:

The two points given are (5, 6) and (15, 14).

Average rate of change is the ratio of the overall change in 'y' and overall change in 'x'. If the overall change in 'y' is positive with 'x', then average rate of change is also positive and vice-versa.

The average rate of change for two points (x_1,y_1)\ and\ (x_2,y_2) is given as:

R=\frac{y_2-y_1}{x_2-x_1}

Plug in x_1=5,x_2=15,y_1=6,y_2=14 and solve for 'R'. This gives,

R= \frac{14-6}{15-5}\\\\R=\frac{8}{10}\\\\R=0.80

Therefore, the average rate of change for the points (5, 6) and (15, 14) is 0.80.

5 0
3 years ago
Square 20cmx20xm
Oxana [17]

Answer:

8,000

Step-by-step explanation:

3 0
3 years ago
The Omicron Model 99 television costs $450. During a special sale, it’s marked 1⁄3 off. How much money will you save buying this
Fudgin [204]

Answer:

225

Step-by-step explanation:

if it is 1/3 off, then it means it's at 2/3 the price. now, you have to divide 450/2 to get the answer. 2/3 divided by 2=1/3

450/2=225, and thats how much money you will save

3 0
1 year ago
Write an equation that expresses the fact that a function f is continuous at the number 4.
vesna_86 [32]
  <span>Use the definition of continuity. 
A function is continuous at a point x = a iff 
lim [x → a] f(x) = f(a) 

In other words, a function is continuous at a point if its value is equal to its limit at that point. 

So, for f(x) to continuous at x = 4 we must have 
lim f(x) = f(4) 
x → 4 



</span>
5 0
3 years ago
Quick algebra 1 question for 50 points!
saul85 [17]

Answer:

b.  -x + y = 0

Step-by-step explanation:

<u />

<u>Direct variation</u>:

Direct variation means "y varies directly as x”:

y \propto x \implies y=kx

where k is the (non-zero) constant of variation.

To determine which of the given equations represents a direct variation, isolate y for each and compare with the <u>direct variation equation</u>.

<u>Equation a</u>

y=\dfrac{4}{3}x-2

This is not a direct variation equation as there is an addition of -2.

<u>Equation b</u>

-x+y=0

\implies y=x

This is a direct variation equation where the constant of variation is 1.

<u>Equation c</u>

xy=8

\implies y=\dfrac{8}{x}

This is not a direct variation equation as y is <u>inversely proportional</u> to x.

<u>Equation d</u>

y=14

This equation does not include the variable x, and so is therefore not a direct variation equation.

3 0
2 years ago
Read 2 more answers
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