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3 years ago

Simplify the following expression. (3x−6)+(5x−5) PLEASE I NEED HELP

Mathematics

2 answers:

Tasya [4]3 years ago

5 0

Answer:

8x-11

Step-by-step explanation:

3x+5x=8x

-6+-5=-11

8x-11

Setler [38]3 years ago

5 0

Answer:

8x-11 hope nthisbelps sorry if im wrong

Step-by-step explanation:

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-2- 3(7-k) =-4(2k-1)

Ivan

Answer:

k=27/11

Step-by-step explanation:

7 0

3 years ago

A rectangular park is 150 yards on one side and 125 yards on the other.

Ket [755]

So, there is a rectangular park with longer side (length) 150 yards and shorter side (width) 125 yards.

so walking around the rectangular park once is like covering the Perimeter (p) of the rectangular park.

So, lets find the perimeter of the park.
Perimeter of rectangle = 2 ( l + w)
= 2 ( 150 + 125 )
= 2 * 275
= 550 yards

Now, walking around the park two times is like doubling the Perimeter of the rectangle. So, when Debbie walks around the park 2 times, he covers the perimeter of the rectangular field twice.

i.e. Debbie walked 2 * Perimeter
= 2 * 550
= 1100 yards

Now, If Debbie wanted to walk 1,000,000 yards, she has to walk the rectangular park (1,000,000 / the Perimeter of the park)
i.e. 1,000,000 / 550
= 1818.18 times

So,
(a) she walks 1100 yards
(b) She have to walk 1818.18 times

4 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Nhan is getting dressed. He considers two different shirts, three pairs of pants, and three pairs of shoes. He chooses one of ea

jekas [21]

Answer:

I have solved this problem on paper (Find pictures attached)

3 0

3 years ago

3a2+4b for a=2 and b=3

Kobotan [32]

First you’ll multiply to get 3x2x2 + 4x3. Then add them together. 12+12=24

4 0

3 years ago