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Ivan
3 years ago
10

Guys please help me man. Please

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

7.4

Step-by-step explanation:

I did this before that's how I know

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Help me please due in 5 minutes
ser-zykov [4K]

Answer:

Step-by-step explanation:

(x - 8)/2 = -5

x - 8 = -10

x = -2

(y + 6)/2 = 10

y + 6 = 20

y = 14

(-2, 14)

3 0
4 years ago
Using the following uniform density curve, answer the question.
Vesnalui [34]

Answer:

The answer is "0.4125"

Step-by-step explanation:

\to 7.4 -4.1= 3.3 (0.125)= 0.4125

8 0
3 years ago
WILL GIVE BRAINLIEST!!!!
Svetradugi [14.3K]

Answer: 8 feet, D

Step-by-step explanation:

To solve this, use the Pythagorean Theorem. It states:

a^{2} +b^{2} =c^{2}

where A and B are the sides of a triangle and C is the triangle's hypotenuse.

The 17 foot ladder in this situation is your hypotenuse, and you have one side of the triangle: 15.

15^2 + b^2 = 17^2

15 squared = 225

17 squared = 289

solving for b squared, we get b^2 = 64

taking the square root of 64, you get 8 feet, the distance between the house and the base of the ladder.

7 0
3 years ago
Rational number<br> between 2 and 3?
oksian1 [2.3K]

Answer:

it would be 7 and 8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The position of a model train, in feet along a railroad track, is given by
miv72 [106K]

Answer:

Part a) The speed is 2.5\frac{ft}{sec}

Part b) After 4 seconds the trains is 24 ft along the track

Part c) t=6\ sec

Step-by-step explanation:

we have

s(t)=2.5t+14

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

m=2.5\frac{ft}{sec}

therefore

The speed is 2.5\frac{ft}{sec}

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

s(4)=2.5(4)+14=24\ ft

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

29=2.5t+14

subtract 14 both sides

29-14=2.5t

15=2.5t

Divide by 2.5 both sides

6=t

rewrite

t=6\ sec

3 0
3 years ago
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