Answer:
BL = 2
Step-by-step explanation:
Given:
AL = 3
AC = 10
BC = 9
AL = AM = 3 (tangents drawn form am external point)
CM = AC - AM
CM = 10 - 3
CM = 7
CM = CN = 7 (tangents drawn form am external point)
BN = BC - CN
BN = 9 - 7
BN = 2
BN = BL = 2 (tangents drawn form am external point).
BL = 2
The sine of 30° is 0.5 .
Angles don't have y-values, and neither do their sines. But
IF you draw a graph of the sine function, AND the angles
(the independent variable) are marked off on the x-axis of
the graph, AND the value of the sine function of each angle
(the dependent variable) is marked off on the y-axis of the
graph, THEN the y-value corresponding to the angle of 30°
would be displayed as 0.5 .
Answer:
5.58*10^7
Step-by-step explanation:
Recall that 10^a*10^b = 10^(a+b). Thus, 10^5*10^2 = 10^7.
Thus, (1.8 x 10^5)(3.1 x 10^2) = (1.8)(3.1)*10^7 = 5.58*10^7
<span> f (x)= 10-x³.
f(2) means the value of the function when x=2.
So, we need to substitute 2 instead of x.
f(2) = 10 - 2³ = 10-8 =2
f(2) = 2
</span>