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3 years ago

6

Answers for the 3 boxes please

2 answers:

puteri [66]3 years ago

7 0

Answer:

-1/7

Step-by-step explanation:

Tomtit [17]3 years ago

3 0

In order for two lines to be perpendicular, their gradients must multiply together to get -1

7*b=-1

7b=-1

Divide both sides by 7

So, the gradient of line b is -1/7

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What does it mean if a check is skipped on a bank statement?

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3 years ago

a memory is a memory from a real event that was encoded, stored, but not retrieved for a long period of time; it is retrieved af

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5 0

1 year ago

What are the coordinates of the vertices of the figure A'B'C'after the following transformation. (x,y) ---> ( y, -x)

topjm [15]

9514 1404 393

Answer:

A'(4, 4)
B'(4, 2)
C'(1, 2)

Step-by-step explanation:

Using the transformation ...

(x,y) ⇒ (y, -x) . . . . . . rotation 90° CW

we have ...

A(-4, 4) ⇒ A'(4, 4)

B(-2, 4) ⇒ B'(4, 2)

C( -2, 1) ⇒ C'(1, 2)

5 0

3 years ago

HELP ASAP PLSSSSSSS

AysviL [449]

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7 0

3 years ago

Please help me!<br> Find the number x such that f(x) =1

STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

3 years ago