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3 years ago

11

Q: Form the differential equation representing the family of curves y = a sin (x + b), where a, b are arbitrary constants.

1 answer:

crimeas [40]3 years ago

8 0

Answer:

y = asin ( x + b)

dy/dx =acos (x+ b)

y²+ (dy/dx)²= a²

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Mr. and Mrs. Garcia took their three children to see a matinee on Saturday . They spent a total of $55.50,1 which included $29.2

zmey [24]

N= number of tickets purchased= 5 people went to the movies
t= cost of each ticket

$55.50 - $29.25= n * t
$55.50 - $29.25= 5t
OR
$55.50= 5t + $29.25

ANSWER: $55.50 - $29.25= 5t OR
$55.50= 5t + $29.25 (there were no equations to choose from, but it should look something like one of these).

Hope this helps! :)

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3 years ago

Solve the equation. 11 6 = n + 7 9 6 11 =n+ 9 7 start fraction, 11, divided by, 6, end fraction, equals, n, plus, start frac

belka [17]

Answer:

n = 19/18

Step-by-step explanation:

Given:

11/6 = n + 7/9

Find n

11/6 = n + 7/9

Subtract 7/9 from both sides of the equation

11/6 - 7/9 = n + 7/9 - 7/9

11/6 - 7/9 = n

(99-42) / 54 = n

n = 57/54

n = 19/18

4 0

3 years ago

nexus9112 [7]

Answer:

Functions: y = -x + 11, y = 2x^2 - 6x + 4, y = 7

Not Functions: x = 3, x^2 + y^2 = 81, y^2 = -5x - 12

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3 years ago

7th grade math help me please :))

ivanzaharov [21]

It decreased from week one to week two by -1.875, then it started to increase from 0.625 then to 1.5 by week 4

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3 years ago

3/5n+15=10+2/5n what is n

Nutka1998 [239]

$\textsf{Hey there!}$

$\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}$

$\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}$

$\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}$

$\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}$

$\textsf{Solve\ the set we have left over}$

$\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}$

$\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}$

$\mathsf{\dfrac{1}{5}n+15-15=10-15}$

$\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }$

$\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }$

$\mathsf{10-15=-5}$

$\mathsf{New\ equation: \dfrac{1}{5}n=-5}$

$\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}$

$\mathsf{\dfrac{1}{5}n\times5=5\times-5}$

$\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \ it \ gives \ us \ 1}$ $\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}$

$\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}$

$\textsf{Thus, \underline{\bf{n = -25}}}\checkmark$

$\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

7 0

3 years ago