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Olegator [25]
3 years ago
12

Find the length of the whole segment in terms of x​

Mathematics
2 answers:
katrin2010 [14]3 years ago
6 0

Answer:

the length of the whole segment is D. 3x + 7

AnnyKZ [126]3 years ago
5 0
The answer is D. 3x+7
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Which triangles are congruent by AAS?
netineya [11]
For two triangles to be congruent by AAS:
1- Two angles in the first triangle must be equal to two angles in the second triangle
2- A non included side in the first triangle is equal to a non included side in the second triangle

Now, let's check our options. We will find that:
For the two triangles UTV and ABC:
angle T = angle A
angle V = angle C
TU (non-included between angles T & V) = AB (non-included between angles A & C)

Therefore, we can conclude that:
Triangles ABC and UTV are congruent by AAS

8 0
3 years ago
Read 2 more answers
Show each step along the Way<br><br>Ur mom
LekaFEV [45]
2x+6 = 20
take 6 from both sides
2x = 14
divide by 2 on both sides
x = 7
8 0
2 years ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
What is the slope of (-3,1) and (0,7)?
Usimov [2.4K]
Over 3 up 6, or better know as 3/6
3 0
3 years ago
MANUFACTURING
Margaret [11]

Answer:

Total cost is $205328

Step-by-step explanation:

Given data:

cost C(q) = 0.1 q^3 - 0.5 q^2 + 500 q + 200

current units q = 4 ( 4000 units )

The current level of production is 4000 ( 4 )units, and manufacturer is planning to upgrade this to 4100 ( 4.1 ) units

C'(q) = 3 * 0.1 q^2 - 2 * 0.5 q + 500

C'(q) = 0.3 q2 - q + 500

C(4.1) - C(4) ≈ C’(4) x Δq

≈ C’(4) x 0.1

≈ ( 0.3 * 4^2 - 4 + 500 ) x 0.1

≈    (  0.3 * 16 - 4 + 500 ) x 0.1

≈    500.8 x 0.1 ≈      50.08

total cost = 4100 x   50.08 = $205328

3 0
3 years ago
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