(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Considering the slopes of the segments, the correct option is:
D. No, because the triangle ABC doesn't have a pair of perpendicular sides.
<h3>When are lines parallel, perpendicular or neither?</h3>
The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:
- If they are equal, the lines are parallel.
- If their multiplication is of -1, they are perpendicular.
- Otherwise, they are neither.
Here, we have to find if there are perpendicular segments, that is, if two slopes multiplied have a value of -1, then:
- mAB = (-7 - 9)/(11 - 1) = -8/5.
- mAC = (3 - 9)/(-9 - 1) = 3/5.
- mBC = (3 - (-7))/(-9 - 11) = -1/2.
No sides are perpendicular, hence option D is correct.
More can be learned about slopes at brainly.com/question/20847660
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Answer:
Option A and D
Step-by-step explanation:
straight lines AI, PR, CT intersect each other at a point k.
Opposite or vertical angles are,
1. ∠ AKC and ∠ TKI
2. ∠ IKR and ∠ AKP
Therefore, options (A) and (D) are the correct options.
Answer: -2
Step-by-step explanation: The line has a slope of -2/1, which is just -2.
