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3 years ago

5

26 joules of heat is used to raise a sample of gold's temperature from 25.0°C to 35.0°C. It's mass is recorded at 20.0 grams. Wh

at is the specific heat of the sample of gold?

1 answer:

Snezhnost [94]3 years ago

7 0

Answer:

0.13

Step-by-step explanation:

change of heat: 35-25 =10 degrees

mass=20

energy=26

c =??

c = Q / (m * ΔT)

=26/20*10= 26/200=0.13 J/g*k

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Which of the following is true about radiation from the sun?

bearhunter [10]

This isn't a math question and should be in the science section. However, I will still answer the question. The answer is choice B.

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Here's a further breakdown

A. False. The radiation or energy from the sun can travel through air or else you wouldn't feel the sun's rays. Also, plant life wouldn't be alive without that energy going through the air.

B. True. The rays travel through a vacuum of space. If they couldn't travel through space, then the same problem comes up as in choice A: the issue of not feeling the sun's rays.

C. False. They rays have different frequencies. Because there are many wavelengths (see choice D below), this means there are different frequencies. Recall that f = 1/w where f is the frequency and w is the wavelength.

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3 years ago

Boden's account has a principal of $700 and a simple

pashok25 [27]

Answer:

823.2

Step-by-step explanation:

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Answer - 823.2

Hope this helps!!!

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2 years ago

1+2+3+4+5+6.......+99 what is the quickest way to find the answer Thank u

serious [3.7K]

Answer:

Step-by-step explanation:

Use the formula Sum = (a + L)*n/2

The tricky part is n. That's the number of terms between 1 and 99 inclusive.

n = 99 -1 + 1 = 99

n = 99

a = 1

L = 99

Sum = (1 + 99)*99 / 2

Sum = (100)*99/2

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3 0

3 years ago

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M+2/3=1/4m-1<br><br><br>what the formula used to find the value of m?

zimovet [89]

<u>Answer:</u>

The value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

<u>Solution:</u>

Given, expression is $m+\frac{2}{3}=\frac{1}{4 m}-1$

Now, we have to solve the above given expression.

$\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1$

By multiplying the equation with m, we get

$\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}$

$\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}$

Now, let us use quadratic formula

$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in our problem, a = 12, b = 20, c = -3

$\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}$

Hence the value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

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3 years ago

NEED HELP ASAP 100PT

Mnenie [13.5K]

Answer:

It is 3 square root of 7

Step-by-step explanation:

:)

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2 years ago

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