How do I solve this properly?
1 answer:
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Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles from 180 for A
A = 180° - (90 + 48)° = 180° - 138° = 42°
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tan48° = =
Multiply both sides by a
a × tan48° = 18 ( divide both sides by tan48° )
a = ≈ 16.2 ( to the nearest tenth )
-----------------------------------------------------------
sin48° = =
Multiply both sides by c
c × sin48° = 18 ( divide both sides by sin48° )
c = ≈ 24.2 ( to the nearest tenth )
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
