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Vesnalui [34]
3 years ago
6

The surface area of a triangular pyramid is 1836 ft2.

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0
1836 ÷ 4 = 459 ft^2   B
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Which one of the following is not equal to 100 meters? 0.100 kilometers 10 hectometers 10,000 centimeters 100,000 millimeters
lara31 [8.8K]
Situation: Which one of the following is not equal to 100 meters?
We were given 4 different choices with corresponding values, not let's start finding the correct answer.
=> 0.100 kilometers
1 meter = 0.001 km 
100 meters = 0.1 km
=> 10 hectometers
1 meter = 0.01 hm
100 meters = 1 hm
=> 10,000 centimeters
1 meter = 100 centimeters
100 meters = 10 000 cm
=> 100,000 millimeters
1 meter = 1000 mm
100 meters = 100 000 mm
<span>thus the not equal answer is hectometer</span>
3 0
3 years ago
In a certain state, car license plates are numbered in the form of LL NNNN, where L stands for a letter of the alphabet and N st
Rashid [163]
L=26
N=10
So it's 26*26*10*10*10*10=6760000
8 0
3 years ago
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vladimir1956 [14]
The slope is 2 because slope formula
6 0
3 years ago
Read 2 more answers
EXTRA POINTS PLEASE HELP I'LL GIVE BRAINLIEST<br> Please write a 2 column proof :)
lidiya [134]

Answer:

Step-by-step explanation:

1). segment AB ≅ segment AE ......... 1). Given

2). ΔBAE is isosceles .............. 2). Definition of isosceles Δs

3). ∠ABC ≅ ∠AEB ............. 3). Corollary to isosceles Δs theorem

4). segment BG ≅ segment EF ........ 4). Definition of midpoints

5). segment BC ≅ segment ED ......... 5) Given

6). segment CD ≅ segment DC ....... 6). Reflexive property

7). segment BD ≅ segment EC ........ 7). Property of sum of equals parts

8). ΔBGD ≅ Δ EFC ............... 8). SAS postulate

9). ∠1 ≅ ∠2 ............ 9). Corresponding parts of congruent Δs

10). ΔCHD is isosceles ............ 10). Corollary to isosceles Δs theorem

7 0
3 years ago
We define a bow-tie quadrilateral as a quadrilateral where two sides cross each other. An example of a bow-tie quadrilateral is
aleksandrvk [35]

Answer:

70/5985

Step-by-step explanation:

We know that a quadrilateral needs to have four vertices (or points on the circle). There are always two ways to link the cross — horizontally or vertically. Using my limited knowledge of combinations, we know that choosing four points out of seven equals 35. Multiplying the two ways to connect those lines (again, horizontally and vertically) makes 35*2 = 70 "bow-tie quadrilaterals" that can be formed on the circle using four points. There are 5985 ways four chords can be chosen out of twenty-five chords because C(25,4) equals 5985, so the probability is 70/5985... and then we just need to simplify that fraction.

3 0
3 years ago
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