<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Answer:
1. 2c+9=m
Step-by-step explanation:
Between 0 and 1, add dashes so you have a total of 6 marks including 0 and 1. Then count 3 over and that would be 3/5.
<span>NEVER use a lower case L as a variable
.
$5M+$8L=$45
.
Medium only:
$5M+$8(0)=$45
$5M=$45
M=9</span>