X^{2} = 49 ............................................
1 answer:
You might be interested in
Remark
If there are 5 distinct zeros that means either that the x axis is crossed the x axis 5 different places or touched the x axis in 1 place out the 5. Touching in one place means that an even number of roots are the same.
So let's go through all of them to get an answer of 5.
A has 4 x intercepts. It is not the right answer. We need 5.
B has 4 x intercepts. It is not the right answer. We need 5.
C has 6 x intercepts. Not the one we want.
D has 5 x distinct zeros. The wording is a bit tricky. It does not matter than one of them just touches the x axis. There could be an even number of distinct zeros there, but it only counts as one root.
An example of such a graph is f(x)=
Answer D <<<<<
If there are 5 distinct zeros that means either that the x axis is crossed the x axis 5 different places or touched the x axis in 1 place out the 5. Touching in one place means that an even number of roots are the same.
So let's go through all of them to get an answer of 5.
A has 4 x intercepts. It is not the right answer. We need 5.
B has 4 x intercepts. It is not the right answer. We need 5.
C has 6 x intercepts. Not the one we want.
D has 5 x distinct zeros. The wording is a bit tricky. It does not matter than one of them just touches the x axis. There could be an even number of distinct zeros there, but it only counts as one root.
An example of such a graph is f(x)=
Answer D <<<<<
Answer:
The cost of the material for the full-sized pad is;
d) 222,750.00
Step-by-step explanation:
The parameters of the steel pad and the scale model are;
The volume of the deck = 18 yd³
The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick
The weight of the sample, m₂ = 75 lbs
The cost of the steel, P = $55/lb
The dimensions of the sample in yards are;
6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0. yards
The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0. yd. = (1/3) yd.³
The density of the sample material, ρ = m₂/V₂
∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³
Therefore, the density of the material of the pad, ρ = 225 lbs/yd³
The mass of the steel pad, m₁ = ρ × V₁
∴ The mass of the steel pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs
The cost of the material for the full-sized steel pad, C = m₁ × P
∴ C = 4,050 lbs × $55/lb = $222,750