$(2x + 5)= (2x + 3)(2x - 1)\\2x+5=4x^2-2x+6x-3\\4x^2-2x+6x-3-2x-5=0\\4x^2+2x-8=0\\(4x+1-\sqrt{33})( 4x+1+\sqrt{33})=0 \\ x=\frac{-1+\sqrt{33} }{4} /or/x=\frac{-1-\sqrt{33} }{4}$

4 0

2 years ago

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10 divided by 2-(16 divided by 4) +14

ankoles [38]

Answer:

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

7 0

3 years ago

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Blake wants to break apart the 7 in 5 × 7. Complete the equation to show two different ways Blake could break apart the 7. Choos

Aleks [24]

5+2=7, so the first blank is 2.
For the second blank, you just need two numbers in the box that when added, equals 7. (So 1,6 or 3,4)

5 0

3 years ago