Answer:
<em>OPtion B. Both the mean and median will increase, but the mean will increase by more than the median.</em>
<em />
Explanation:
You should not need to do calculations to determine <em>how buying the horse affects the mean and median.</em>
Without the horse, there are 8 animals. When the data are ordered, the <em>median</em> is the average of the 4th and the 5th weights: (7 + 27)/2.
With the horse, there are 9 animals. The median will be the 5th weight: 27
Then, the median increases from (7 +27)/2 to 27.
What about the <em>mean</em>?
The horse's weight is well beyond the weight of the other 8 animals. The range increases from 160 - 2 = 158 to 900 - 2 = 898.
Then, when you calculate the mean inlcuding the weigth of the horse, there will be a high increase.
Thus, without further calculations, you can conclude that "<em>B. Both the mean and median will increase, but the mean will increase by more than the median"</em>
