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disa [49]
3 years ago
7

A matchbox tray slides into its outer cover in how many different ways can you do this

Mathematics
1 answer:
Leni [432]3 years ago
4 0
-- Slide end-A of the tray, right-side-up, into end-A of the cover.    (0 0 0)
-- Slide end-A of the tray, right-side-up, into end-B of the cover.    (0 0 1)
-- Slide end-A of the tray, upside-down, into end-A of the cover.    (0 1 0)
-- Slide end-A of the tray, upside-down, into end-B of the cover.    (0 1 1)
-- Slide end-B of the tray, right-side-up, into end-A of the cover.    (1 0 0)
-- Slide end-B of the tray, right-side-up, into end-B of the cover.    (1 0 1)
-- Slide end-B of the tray, upside-down, into end-A of the cover.    (1 1 0)
-- Slide end-B of the tray, upside-down, into end-B of the cover.    (1 1 1)






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Pls i need it like now
schepotkina [342]
You need to put the x or y value in the other equation ;
For example excersize a
It given that
Y=x^2+3x-1
Then you put it on the first equation :
x+x^2+3x-1=4
And then you solve it
x+x^2+3x-1-4=0
4x+x^2-5=0
We will make the order to seem easier
x^2+4x-5=0
x1=-5
x2=1
Then you put the x1,2 that you found on the second equation :
y=(-5)^2+3*(-5)-1=9
y=1^2+3*1-1=3
For summary :
x1=-5
x2=1
y1=9
y2=3

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ira [324]

Answer:

False

Step-by-step explanation:

The coefficients (numbers in front) don't matter, but the exponents do.

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54x^2y^3\text{ and }-12x^3y^2 are not like terms.

Example: 6x^3y^2\text{ and }-14x^3y^2 <u>are</u> like terms--same exponents on the x's, same exponents on the y's.

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