This is an exponential function.
If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.
Make a table and graph the points:
x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.
The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.
Answer:
False hope this helps
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
DB = 9 units (by counting)
BA = 12 units (by counting)
DA can be found by using the pythagorean theorem
a^2 +b^2 = c^2
BD^2 + BA^2 = DA ^2
9^2 +12^2 = DA^2
81 +144 = DA^2
225 = DA ^2
Take the square root of each side
sqrt(225) = sqrt(DA^2)
15 = DA
LJ = 3 units (by counting)
JK = 4 units (by counting)
LK can be found by using the pythagorean theorem
a^2 +b^2 = c^2
LJ^2 + JK^2 = LK ^2
3^2 +4^2 = LK^2
9 +116 = LK^2
25 = LK ^2
Take the square root of each side
sqrt(25) = sqrt(LK^2)
5 = LK
Scale factor from BAD to JKL
15 to 5
Divide each side by 5
3 to 1
We multiply by 1/3 to go from the big to small
Answer:
78º
Step-by-step explanation:
<u>Note</u> : -
In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the
x - axis.
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -
Find where 192º lies in which quadrant.
192º lies in 3rd quadrant ( between
180º and 270º )
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -
Subtract : 270 - 192
270 - 192 = 78º
( Since, 192º is greater than 180º, is subtracted from 270º )
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -
78º is the reference angle for 192º.
