Question

HELP ASAP Find the zeros of y = x^2 - 4x - 9 by completing the square.

Answer 1

The given equation is :

$y=x^{2} -4x-9$

Replacing y as zero, we get,

$x^{2} -4x-9=0$

Now solving this quadratic equation using formula:

$x1,2=\frac{-b+\sqrt{b^{2}-4ac}}{2a}$ and

$x1,2=\frac{-b-\sqrt{b^{2}-4ac}}{2a}$

Putting a=1, b=-4, c=-9 we get

$x=2+\sqrt{13}$ and $x=2-\sqrt{13}$

So, option B is the correct answer.

Answer 2

Answer: x= 2 + √ 13 ,2- √ 13

Step-by-step explanation:

Replace y with 0 and solve for x