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Korolek [52]
3 years ago
14

HELP ASAP Find the zeros of y = x^2 - 4x - 9 by completing the square.

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
5 0

The given equation is :

y=x^{2} -4x-9

Replacing y as zero, we get,

x^{2} -4x-9=0

Now solving this quadratic equation using formula:

x1,2=\frac{-b+\sqrt{b^{2}-4ac}}{2a} and

x1,2=\frac{-b-\sqrt{b^{2}-4ac}}{2a}

Putting a=1, b=-4, c=-9 we get

x=2+\sqrt{13} and x=2-\sqrt{13}

So, option B is the correct answer.

Alla [95]3 years ago
4 0

Answer: x= 2 + √ 13 ,2- √ 13

Step-by-step explanation:

Replace y with 0 and solve for x

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-----------------------------------------------------
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