A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
Answer:
(4, 0)
Step-by-step explanation:
The circumference of a circle is
where <em>r</em> is the radius.
In this case,
. Divide both sides of the equation by
to get
![r=5](https://tex.z-dn.net/?f=r%3D5)
The center of the circle is on the <em>x</em>-axis, so the intercepts are 5 units to the left of the center and 5 units to the right of the center. The two intercepts are (-1-5, 0) and (-1+5, 0). The point that is on the positive <em>x</em>-axis is (4, 0).
See attached image.