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3 years ago

How do you find prime factorization?

Mathematics

1 answer:

skad [1K]3 years ago

6 0

You can use a factor tree, and if you dont know how to use one, look it up on youtube, theres tons

You might be interested in

Write the polynomial function of least degree that has zeros of x=-i and x=1

stepan [7]

Answer:

(x-1)(x^2 + 1)

Step-by-step explanation:

If the polynomial has two roots or zeros, then the least degree it can be is 2. But when x = -i is a root, generally x = i is a root too. Thus the degree here is 3. Using the roots, you can write the polynomial by finding a factor from each. The zeros are the solution to the factor. So if x = 1, it came from the factor x - 1. x = 1 is the solution because x - 1 = 0 is x = 1 solved.

When x = -i, i this is the result of a square root of a negative number. So x had the exponent 2. To write the factor for x = -i, you should write x^2 + 1. When solved x = +/-√-1 = +/- i.

The function is likely (x-1)(x^2 + 1).

6 0

3 years ago

Find the area of the parrallelogram

Zolol [24]

Answer:

I believe it is about 47.63 meters squared

Leave a comment if you'd like a step-by-step explanation

5 0

3 years ago

Find the distance between the point (-2, -3) and the line with the equation y=4-2/3x

otez555 [7]

Answer:

$D = \frac{25\sqrt{13}}{13}$

Step-by-step explanation:

Given

$y = 4 - \frac{2}{3}x$

$(x_1,y_1) = (-2,-3)$

Required

Determine the distance

$y = 4 - \frac{2}{3}x$

Write the above equation in standard form:

$Ax + By + C = 0$

So, we have:

$\frac{2}{3}x+y - 4 = 0$

By comparison:

$A = \frac{2}{3}$ $B = 1$ and $C = -4$

The distance is calculated using:

$D = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$

Where:

$(x_1,y_1) = (-2,-3)$

$A = \frac{2}{3}$ $B = 1$ and $C = -4$

This gives:

$D = \frac{|\frac{2}{3} * (-2) + 1 * (-3) - 4|}{\sqrt{(\frac{2}{3})^2 + 1^2}}$

$D = \frac{|-\frac{4}{3} -3 - 4|}{\sqrt{\frac{4}{9} + 1}}$

Take LCM

$D = \frac{|\frac{-4-9-12}{3}|}{\sqrt{\frac{4+9}{9}}}$

$D = \frac{|\frac{-25}{3}|}{\sqrt{\frac{13}{9}}}$

$D = |\frac{-25}{3}|/\sqrt{\frac{13}{9}}$

$D = \frac{25}{3}/\sqrt{\frac{13}{9}}$

Split the square root

$D = \frac{25}{3}/\frac{\sqrt{13}}{\sqrt{9}}$

Change / to *

$D = \frac{25}{3}*\frac{\sqrt{9}}{\sqrt{13}}$

$D = \frac{25}{3}*\frac{3}{\sqrt{13}}$

$D = \frac{25}{\sqrt{13}}$

Rationalize

$D = \frac{25}{\sqrt{13}} * \frac{\sqrt{13}}{\sqrt{13}}$

$D = \frac{25\sqrt{13}}{13}$

Hence, the distance is:

$D = \frac{25\sqrt{13}}{13}$

4 0

3 years ago

Given the following rectangle and circle, at what approximate value of x are the two areas equal? x ≈ 5.8 x ≈ 3.4 The curves do

SIZIF [17.4K]

The approximate value of x will be approximately equal to 3.4

<h3>Area of triangle and circle</h3>

The formula for calculating area of rectangle is expressed as:

A = lw

l is the length
w is the width

Ar = (3x-1)(x+2)

Ar = 3x^2+6x-x-2

Ar = 3x^2 + 5x - 2

For the circle

Ac = πr²

Ac = 3.14(x-3)²

Ac = 3.14(x²-6x+9)

Ac = 3.14x² - 18.84x + 28.26

If the area are equal;

3x² + 5x - 2 = 3.14x² - 18.84x + 28.26

3.14x² - 3x² - 5x - 18.84x + 30.26 = 0
0.14x²-23.84x+30.26 = 0

On factorizing the equation, the approximate value of x will be approximately equal to 3.4

Learn more on area of rectangle here; brainly.com/question/25292087

6 0

2 years ago

Someone please help me!!

Black_prince [1.1K]

Answer:

Step-by-step explanation:

All the interior angles of a triangle add up to 180 degrees

3 0

2 years ago