Answer:
Step-by-step explanation:
A box contains four cards: One card is black on both sides, one card is red on both sides and two cards are black on one side and red on the other side. One card is selected at random and you can see only one side.i) If the side you see is black, what is the probability that the other side is black?ii) If the side you see is black, what is the probability that the other side is red?
Given that:
Number of cards = 4
x = Black on both sides = 1
y = Red on both sides = 1
z = Black on one side, red on one side = 2
.i) If the side you see is black, what is the probability that the other side is black = b
Probability of black
P(x) = 1/4 ; p(b|x) = 1
P(y) = 1/4 ; p(y|x) =
Ln20+ln5=2lnx
ln(20x5)=lnx^2
ln100=1nx^2
100=x^2
square root
x=10
I don’t see anything. What is the problem.
You just need to multiply 14 miles by 14 days so the answer is 196
