Answer:
C
Step-by-step explanation:
Its C because its x (a variable) and is costanly changing
The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.
Step-by-step explanation:
The given is,
Volume of aluminium available is 1000 cubic centimeters
Shape of trophy is right square pyramid
Trophy has a base edge of 10 cm and slant height of 13 cm
Step:1
Formula for volume of right square pyramid,
.....................................(1)
Where, a - Base edge value
h - Height of pyramid
From given,
a = 10 cm
h = 13 cm
Equation (1) becomes,


Volume of trophy = 433.33 cubic centimeters
Compare with the volume of available aluminium and volume of right square pyramid,


So, the given volume of aluminium is enough to make right square pyramid shaped trophy.
Result:
The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.
Answer:
It is the first answer
Step-by-step explanation:
For it to be considered a function, each x-value can only corresponds (have) one y-value, however, y-values (even if they are the same y-value) can have multiple different x-values.
Answer:
6√x
Step-by-step explanation:
9√x - 3√x = 6√x
Answer:
<em>0 $20 bills and 10 $5 bills</em>
<em>1 $20 bills and 6 $5 bills</em>
<em>2 $20 bills and 2 $5 bills</em>
Step-by-step explanation:
<u>Equations</u>
Let's set:
x=number of $5 bills
y=number of $20 bills
The total amount Sara has is given by
5x+20y
And we know it's equal to $50, thus:
5x+20y=50
Dividing by 5
x+4y=10
We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.
Solving for x:
x=10-4y
Since both x and y are integers and cannot be negative:
10-4y≥0
Swapping sides:
4y≤10
Dividing by 4:
y≤2.5
Thus, y can only have the values {0,1,2}
For y=0
x=10-4*0=10
x=10
For y=1
x=10-4*1=6
x=6
For y=2
x=10-4*2=2
x=2
Thus, the possible combinations are:
0 $20 bills and 10 $5 bills
1 $20 bills and 6 $5 bills
2 $20 bills and 2 $5 bills