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Naya [18.7K]
3 years ago
12

What is a simplified form of the expression 7x – 5(x + 1)?

Mathematics
2 answers:
Viefleur [7K]3 years ago
4 0
2x-5 - answer

i hope this helps
Maru [420]3 years ago
3 0

Answer:2.5

Step-by-step explanation:

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3a + 18

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If angle ABC equals 130, what would the vertical angle equal to?
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400

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How do I do this please help I'm in tears
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F(x) is vertically stretched by a factor of 5/4 matches w/ f(x)-5/4
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f(x) translated 5/4 to the left matches w/ f(x)-5/4

I didn't really know about this one but it seemed kind of easy, what was your first guesses and did you forget to put one more or was the question like that.


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Jeff has a square piece
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3 years ago
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A study of college football games shows that the number of holding penalties assessed has a mean of penalties per game and a sta
Alisiya [41]

Answer:

The probability that the mean number of holding penalties per game is of X or less is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean number of penalties per game, \sigma is the standard deviation and n is the number of games that will be sampled.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have that:

The mean number of penalties per game is \mu and the standard deviation is \sigma.

Sample of n games:

This means that s = \frac{\sigma}{\sqrt{n}}

What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?

The probability that the mean number of holding penalties per game is of X or less is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean number of penalties per game, \sigma is the standard deviation and n is the number of games that will be sampled.

4 0
3 years ago
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