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Naddika [18.5K]
3 years ago
9

Evaluate 4.68 + 2.7 + 13.289

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

20.669

Step-by-step explanation:

Ymorist [56]3 years ago
3 0
The sum of the answer is 20.669

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alonzo has bought 30 pounds of dog food. he feeds his dog 2/3 pounds for each meal. for how many meals will the food last? write
True [87]

Answer:

45 meals.

Step-by-step explanation:

Answer:

45 meals

Explanation:

Given :

Alonzo has bought 30pounds of dog food

He feed his dog 2/3 ponds for each meal,

To Find :

How meals will the food last

Solution :

Total pounds he bought => 30

He feeds 2/3 pounds in each meals

Therefore, consumed in each meal  =>

Therefore, food will last for 45 meals

8 0
3 years ago
Read 2 more answers
If P(A or B) = 0.8, P(A) = 0.3, and P(A and B)= 0.15, find P(B).
Dennis_Churaev [7]

9514 1404 393

Answer:

  P(B) = 0.65

Step-by-step explanation:

The appropriate formula is ...

  P(A or B) = P(A) +P(B) -P(A and B)

Then P(B) is ...

  P(B) = P(A or B) +P(A and B) -P(A)

  P(B) = 0.8 +0.15 -0.3

  P(B) = 0.65

7 0
3 years ago
A party there was four large Submarine sandwiches at all the same size during a party two-thirds of the chicken sandwich and 3/4
Mekhanik [1.2K]

Answer:

69%

Step-by-step explanation:

4 0
3 years ago
What is the domain of the function y = StartRoot x + 6 EndRoot minus 7? x greater-than-or-equal-to negative 7 x greater-than-or-
VARVARA [1.3K]

Answer:

Domain= {x\geq -6}

Step-by-step explanation:

The function given is: f(x)=\sqrt{x+6} -7, and we are asked to find the Domain of it. Let's recall that the Domain of a function is the set of all x-values for which the function is defined (can be evaluated rendering a real number as result). So in order to find which x-values constitute such Domain, let's investigate for which x-values we can effectively evaluate the square root of "x+6".

Notice that the square root is not defined for radicands that are negative (less than zero). The only radicands that are allowed are those greater than or equal to zero. So that is exactly the condition we want to impose on the radicand: to be greater than or equal to zero (\geq 0). Our radicand is the expression: "x+6", so we write in math terms the necessary condition as:

x+6\geq 0

and solve for "x" in the inequality (isolating "x" on one side:

x+6\geq 0\\x\geq -6

The Domain of this function is therefore all those real "x" values that are greater than or equal to negative 6 (x\geq -6)

3 0
3 years ago
Read 2 more answers
What additional piece of information do we need to prove that MLN ≅ OPN
mote1985 [20]

Answer:

N is the midpoint of MO

Step-by-step explanation:

Given

See attachment for triangles

Required

Additional information to prove MLN \cong OPN

From the attachment, we already have:

LM \simeq OP and LN \simeq ON

The additional information that must be true for MLN \cong OPN  to be true is: <em>N is the midpoint of MO</em>

Because this piece of information proves that:

MN \simeq ON

<em>Which in other words makes </em>MLN \cong OPN<em> </em>

6 0
3 years ago
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