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Ugo [173]
3 years ago
8

What is the domain of the function y = StartRoot x + 6 EndRoot minus 7? x greater-than-or-equal-to negative 7 x greater-than-or-

equal-to negative 6 x greater-than-or-equal-to 6 x greater-than-or-equal-to 7
Mathematics
2 answers:
kari74 [83]3 years ago
6 0

Answer: Option B

x>-6

Step-by-step explanation:

its the answer on edge

VARVARA [1.3K]3 years ago
3 0

Answer:

Domain= {x\geq -6}

Step-by-step explanation:

The function given is: f(x)=\sqrt{x+6} -7, and we are asked to find the Domain of it. Let's recall that the Domain of a function is the set of all x-values for which the function is defined (can be evaluated rendering a real number as result). So in order to find which x-values constitute such Domain, let's investigate for which x-values we can effectively evaluate the square root of "x+6".

Notice that the square root is not defined for radicands that are negative (less than zero). The only radicands that are allowed are those greater than or equal to zero. So that is exactly the condition we want to impose on the radicand: to be greater than or equal to zero (\geq 0). Our radicand is the expression: "x+6", so we write in math terms the necessary condition as:

x+6\geq 0

and solve for "x" in the inequality (isolating "x" on one side:

x+6\geq 0\\x\geq -6

The Domain of this function is therefore all those real "x" values that are greater than or equal to negative 6 (x\geq -6)

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(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +
jekas [21]

Answer:

1. The slope of the line is m=\frac{-2b+3}{2a}.

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

m=\frac{-b-(b-3)}{a+3-(-a+3)}

m=\frac{-b-b+3}{a+3+a-3)}

m=\frac{-2b+3}{2a}

The slope of the line is m=\frac{-2b+3}{2a}.

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

m_1=\frac{5-1}{6-a}=\frac{4}{6-a}

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

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The slopes of two parallel lines are same.

m_1=m_2

\frac{4}{6-a}=\frac{-6}{a}

On cross multiplication we get

4a=-6(6-a)

4a=-36+6a

4a-6a=-36

-2a=-36

Divide both sides by -2.

a=18

Therefore the value of a is 18.

8 0
3 years ago
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