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bazaltina [42]
3 years ago
11

Please help I’ll give brainliest!!!! What is a minimum of 3 examples of polynomials?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

4x + 3

10x² - 7x + 3

18x² - x + 5

Step-by-step explanation:

A polynomial must consist of 2 terms, one with a variable ( x ) and one as a constant ( any number )

An example of a number with a variable is 4x

An example of a constant is 3

add the two together 4x + 3 and you get a polynomial

More examples are 5x + 9 or -2x - 8

Polynomials can have more than 2 terms. ( the third term has an exponent and variable )

An example of a polynomial with more than 2 terms  is 10x² - 7x + 3

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Answer:

b = 12

Step-by-step explanation:

a^2 + b^2 = c^2

25 + b^2 = 169

b^2 = 144

b = 12

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2 years ago
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How many pennies could you have if: When you Break de Pennies into groups of 2, you have 1 penny left over, AND when you break t
MariettaO [177]

Answer:

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is  not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

6 0
3 years ago
PLEASE HELP!!! PLEASE SHOW ALL OF YOUR WORK!!!
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The answer is c bc I just know
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