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3 years ago

Round 71290 to the nearest 10 what's the answer?

1 answer:

6 0

71290 because the ones are 0 and zero is lower than 5
so it wouldn't add anything to the tens

the rule is if the number is more than 5+ it will add 1 to the next number
for example if we have this number 189 and we want to round it to the nearest 10 ..
we will see the ones place is it more than 5+ ? YEAH bcz its 9 ...
so 9 will add one to the tense and the answer will be 190 :)

hope you got the point .

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The side lengths of the following right triangle 15,20 and 25, as shown below. The altitude from the right angle splits the hypo

kompoz [17]

Answer:

$h = 12$

$x = 9$

$y= 16$

Step-by-step explanation:

Given

The attached triangle

Required

Find h, x and y

Let the base of the triangle be 15.

So, the area is:

$A = \frac{1}{2} * 15 * 20$

$i.e\ height = 20$

$A = \frac{1}{2} * 300$

$A = 150$

Let the base of the triangle be 25.

So, the area is:

$A = \frac{1}{2} * 25 * h$

$i.e\ height = h$

$A = \frac{1}{2} * 25h$

Substitute $A = 150$

$\frac{1}{2}*25h = 150$

Solve for h

$h = \frac{150 *2}{25}$

$h = 6 *2$

$h = 12$

Considering the smallest triangle

$Hypotenuse = 15$

So:

$15^2 = h^2 + x^2$

$15^2 = 12^2 + x^2$

This gives:

$15^2 - 12^2 = x^2$

$81 = x^2$

Take square roots

$9 =x$

$x = 9$

Solving for y

$x + y = 25$

$y= 25 - x$

$y= 25 - 9$

$y= 16$

7 0

2 years ago

Pls I need help this

Citrus2011 [14]

Answer:

the third side is 4.

Step-by-step explanation:

Using Pythagorean theorem of a^2 + b^2 = c^2 for right triangles, substitute

the numbers to show ( $\sqrt{65})^{2}$ + $b^{2}$ = $9^{2}$ and solve for b. The square root and square cancel each other out, so you get 65 + $b^{2}$ = 81.