Find the area of the circle. Use 3.14 for pi. 24 ft

Find the square: (5x - 4y)2 <br><br> (and please put the process of solving the equation)

satela [25.4K]

$(5x-4y)^2$
$(5x-4y)(5x-4y)$

Multiply each term in one bracket in turn by the terms in the other bracket

$(5x)(5x) = 25x^2$
$(5x)(-4y)=-20xy$
$(-4y)(5x)=-20xy$
$(-4y)(-4y)=16y^2$

Put them together we have
$25x^2-20xy-20xy-16y^2$
$25x^2-40xy-16y^2$

7 0

3 years ago

This morning, Maria's car had 16.03 gallons of fuel. Now, 2.9 gallons are left. How much fuel did Maria use?

Vadim26 [7]

Answer:

take 16.03 and subtract 2.9

16.03-2.9=13.13

so maria used 13.13 gallons

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a

Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

$f(x)=x^2$

$g(x)=|x|$

It is given that,

$(f\circ g)(x)=|x|^2=x^2$

$(g\circ f)(x)=|x^2|=x^2$

According to chin rule,

$(f\circ g)(c)=f(g(c))=f'(g(c)g'(c)$

It means, $(f\circ g)(c)$ is differentiable if f(g(c)) and g(c) is differentiable at x=c.

Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule

3 0

3 years ago

A random sample of 11 nursing students from Group 1 resulted in a mean score of 41.3 with a standard deviation of 6.8. A random

Lina20 [59]

Answer:

At 1% significance level, this difference is considered to be extremely statistically significant.

Step-by-step explanation:

Group Group One Group Two

Mean 41.300 54.800

SD 6.800 6.000

SEM 2.050 1.604

N 11 14

H0: Mean of group I = Mean of group II

Ha: Mean of group I < mean of group II

(Left tailed test at 1% significance level)

The mean of Group One minus Group Two equals -13.500

standard error of difference = 2.563

t = 5.2681

df = 23

p value= 0.00005

Since p < significance level, reject H0

6 0

3 years ago

On a recent trip to a local orchard, the Morgan family picked four different kinds of apples - Braeburn, Cortland, Fuji, and Rom

ivanzaharov [21]

Answer:

Morgan family picked 144 Braeburn apples, 96 Cortland apples, 72 Fuji apples and 48 Rome apples.

Step-by-step explanation:

Let B, C, F and R represent Braeburn apples, Cortland apples, Fuji apples, and Rome apples respectively.

We have been given that Morgan family picked a total of 360 apples. We can represent this information in an equation as:

$B+C+F+R=360...(1)$

We are told that Morgan family picked twice as many Braeburn as Fuji. We can represent this information in an equation as:

$B=2F...(2)$

We are told that Morgan family picked twice as many Cortland as Rome, that is:

$C=2R...(3)$

We are told that Morgan family picked 50% more Fuji than Rome, that is:

$F=1.5R...(4)$

Upon substituting equation (4) in equation (2), we will get:

$B=2(1.5)R$

$B=3R$

Now, each apple in in terms of Rome apples, so we will get:

$3R+2R+1.5R+R=360$

Let us solve for R.

$7.5R=360$

$\frac{7.5R}{7.5}=\frac{360}{7.5}$

$R=48$

Therefore, Morgan family picked 48 Rome apples.

Upon substituting $R=48$ in (3), we will get:

$C=2R\Rightarrow 2(48)=96$

Therefore, Morgan family picked 96 Cortland apples.

Upon substituting $R=48$ in (4), we will get:

$F=1.5R\Rightarrow 1.5(48)=72$

Therefore, Morgan family picked 72 Fuji apples.

Upon substituting $F=72$ in (2), we will get:

$B=2F\Rightarrow 2(72)=144$

Therefore, Morgan family picked 144 Braeburn apples.

3 0

3 years ago