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lesantik [10]
3 years ago
11

Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.

Mathematics
2 answers:
Vikentia [17]3 years ago
7 0

Answer:

(2.5, -1)

(-2.5, 1)

(-1, 2.5)

Step-by-step explanation:

alukav5142 [94]3 years ago
4 0

Answer:

(2.5, -1)

(-2.5, 1)

(-1, 2.5

Step-by-step explanation:

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Given that f(x)=2x/3 evaluate f^-1(6)
abruzzese [7]

Answer:

9

Step-by-step explanation:

we know by definition that

f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}

so now we evaluate

f^{-1}(6)=\frac{3*6}{2}\\\\=3*3\\\\f^{-1}(6)=9

and if we want to do an extra step

f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6

which works.

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3 years ago
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C

Step-by-step explanation:

5 0
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