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Afina-wow [57]
3 years ago
8

Johann uses 42 ÷ 7 to represent the number of players who are on teams. Explain what 42 ÷ 7 means. Enter a number in each box. 4

2 ÷ 7 means that [blank] players are on teams in all and that each team has [blank] players.​
Mathematics
1 answer:
ankoles [38]3 years ago
8 0
42 players are on teams in all and that each team has 6 players. This is correct if the number 7 is referring to the number of teams.
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What's the area of the composite figure below ?
JulsSmile [24]

Answer:

31.13

Step-by-step explanation:

If you look carefully, you will find a semicircle and a triangle.

The total area is =

\frac{\pi r^{2}}{2} + \frac{1}{2} \times base \times height\\

  • r = 4 - 0 = 4
  • base = |-4-0 | = 4
  • height = 14 - 9 = 5

So if we put the values:

\frac{\pi \times 4^{2}}{2} + \frac{1}{2} \times 4 \times 3\\= 31.13

3 0
3 years ago
Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
Find the area of the figure below:
Afina-wow [57]

Answer:

60.75 m^2

Have a great day

6 0
3 years ago
Point B is AC between A and C. If AB is doubled and BC is also doubled, predict the effect on AC.
Elena-2011 [213]
AC would also be divided by two then

3 0
3 years ago
Read 2 more answers
Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .
stich3 [128]

\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}


\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}

4 0
3 years ago
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